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Wipro Limited Interview Guide
For Freshers — India 2026
Easy Difficulty💰 ₹3.5–6.5 LPA👥 20,000+ freshers/year📝 4 Questions
About the Wipro Interview Process
Wipro's National Level Talent Hunt (NLTH) is the primary fresher hiring channel. The difficulty is moderate and focuses on aptitude and basic programming. The Elite track offers ₹6.5 LPA.
Interview Rounds
- 1Wipro NLTH (Online Test)
- 2Technical Interview
- 3HR Interview
Insider Tips to Crack Wipro
- ✓Wipro NLTH has three sections: Aptitude, Written Communication, and Coding
- ✓The coding section allows any language — Python preferred for speed
- ✓Written communication: write a 200-word essay on a given topic clearly
- ✓Technical round focuses on your project — prepare a 2-minute project walkthrough
- ✓Wipro culture is work-life balanced — mention this in HR if relevant
Wipro Interview Questions & Answers
Q1. What is the difference between stack and queue?
TechnicalModel Answer:
Stack: LIFO (Last In First Out) — push/pop from top. Used in: function calls, undo operations. Queue: FIFO (First In First Out) — enqueue at rear, dequeue from front. Used in: OS scheduling, BFS. Both can be implemented with arrays or linked lists.
Q2. Explain HTTP vs HTTPS.
TechnicalModel Answer:
HTTP (HyperText Transfer Protocol) transfers data in plain text — insecure. HTTPS adds TLS/SSL encryption, ensuring data confidentiality, integrity, and server authentication. HTTPS uses port 443, HTTP uses port 80. All modern sites use HTTPS — browsers warn users about HTTP sites.
Q3. Why do you want to join Wipro?
HR / BehavioralModel Answer:
'Wipro's breadth across BFSI, healthcare, and retail means I'll work on diverse problems. I'm also attracted to Wipro's focus on sustainability — it aligns with my values. The NLTH Elite track shows Wipro values technical merit, which motivated me to prepare seriously.'
Q4. Find the factorial of a number using recursion.
CodingModel Answer:
```python
def factorial(n):
if n <= 1: return 1
return n * factorial(n-1)
```
Base case: factorial(0) = factorial(1) = 1. Recursive case: n * factorial(n-1). Note: iterative is better for large n (no stack overflow).
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